How to get system date in cl program iso#
How to get system date in cl program free#

By this you can obtain the age in the simplest possible way:

Net nor any official rule supports this, nor does common logic explain why some born in February should have 75% of their birthdays in another month.ДЇurther, an Age method lends itself to be added as an extension to DateTime. is the birthday of leaplings but neither. of leap years and obtain the correct result of the 28th of Feb. The simple answer to this is to apply AddYears as shown below because this is the only native method to add years to the 29th of Feb. Public int CalculateAgeWrong2(DateTime birthDate, DateTime now) Return new DateTime(now.Subtract(birthDate).Ticks).Year - 1 Here you have the methods: public int CalculateAgeWrong1(DateTime birthDate, DateTime now) MessageBox.Show(string.Format('Test ',Д¬alculateAgeWrong1(bDay, now), // outputs 9Д¬alculateAgeWrong2(bDay, now), // outputs 9Д¬alculateAgeCorrect(bDay, now), // outputs 8Д¬alculateAgeCorrect2(bDay, now))) // outputs 8 That's how easy it is to convert from any standard format to any other standard format.Here is a test snippet: DateTime bDay = new DateTime(2000, 2, 29) ДateTime now = new DateTime(2009, 2, 28) %dec( %char( %date(num_date : *iso) : *usa0) : 8 : 0)Д«e sure to specify the correct length, in this case 8-bytes for MMDDYYYY and zero (0) decimal positions. The format specified on the %date BIF indicates what you are converting from the format specified on the %char BIF indicates what you are converting to.Д¬onverting to a numeric field requires just one additional step: convert the alpha date to numeric using the %dec BIF: Remember that the inner conversion takes place first (%date), followed by the outer conversion (%char). %char( %date(num_date : *iso) : *usa) //Output MM/DD/YYYY %char( %date(num_date : *iso) : *usa0) //Output MMDDYYYY

If I want to convert from an 8-byte numeric YYYYMMDD date to a 10-character alpha MM/DD/YYYY date I can do it in one statement:

How to get system date in cl program free#

The nice thing about using BIFs (and especially in free format) is that you don't need to do separate steps to get your result. If you want the same date but no separators: For example, if you want to create a character date as MM/DD/YYYY, specify: To convert a date data-type to an alpha format, use the %CHAR BIF and specify the format that you want to receive. Now that you have your date as a date data type, it's time to convert it to the format of your choice. If you store valid separators with your date but not the default for the format (MM-DD-YY in an 8-byte character field), then the default separator is the slash (/) and you indicate the separator at the end of the format name:ДЄs you can see, as long as you have your dates in one of the 12 standard formats, it's pretty easy to convert it to a date data type. If you do not store standard separators with your date (YYYYMMDD in an 8-byte character field) simply append the number zero (0) to the end of the format name:

How to get system date in cl program iso#

For example, if your date is in a 10-byte character field as YYYY-MM-DD (with the dashes), this is again ISO format: In this case all I change is the format on the %date BIF:ДЇor anyone storing dates in alpha fields, the format you specify will depend on whether or not you store the date separators. We also have a few dates stored as MMDDYYYY in 8-byte numeric fields. The '*iso' tells the %date BIF how my numeric date field (num_date) is formatted. We can convert this to a date data type with the following code: This is the numeric version of the ISO format. Most of our dates are stored as YYYYMMDD in 8-byte numeric fields. If your dates come in one of the 12 standard formats all you need to do is indicate the field containing your date and the format it is in and the %DATE BIF does the rest. If used with no parameters, %date will return the current system date. To populate a date variable from something other than a literal string, you have to use the IBM-supplied %date BIF.